If (x1, y1) and (x2, y2) are two points or coordinates in XP plane, then we can find the distance between them by following mathematical distance formula: This formula was made from Pythagoras triangle theorem.

Now let’s see how to find distance between two points in Java:
If (x1, y1) and (x2, y2) are two points or coordinates in XP plane, then following java console program shows the distance between them.

 import java.io.*; class distance {    int x1,y1,x2,y2,difx,dify;    double d; void get() throws IOException   {      BufferedReader Br = new BufferedReader(new InputStreamReader(System.in));      System.out.print("\n Enter the X part of first point : ");      x1=Integer.parseInt(Br.readLine()); System.out.print(" Enter the Y part of first point : ");      y1=Integer.parseInt(Br.readLine()); System.out.print("\n Enter the X part of second point : ");      x2=Integer.parseInt(Br.readLine()); System.out.print(" Enter the Y part of second point :  ");      y2=Integer.parseInt(Br.readLine());   } void display()   {         difx = (x2 - x1) * (x2 - x1);  dify = (y2 - y1) * (y2 - y1);  d = Math.sqrt(difx + dify);       System.out.println("\n Distance between (" + x1 + "," + y1 + ") and (" + x2 + "," + y2 + ") is : " + d + " unit(s) " );   }  public static void main(String p[]) throws IOException  {    distance dis = new distance();    dis.get();    dis.display();  } }

Sample Output:
Enter the X part of first point : 1
Enter the Y part of first point : 4

Enter the X part of second point : 4
Enter the Y part of second point : 0

Distance between (1, 4) and (4, 0) is : 5.0 unit(s).